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const goBack = 3; for (let i = 0; i < goBack; i++) d.setDate(0); d.setDate(day); This will give you the date of today's date 3 months ago as .setDate(0) sets the date to the last day of last month irrespective of how many days a month contains. day is used to restore today's date value. answered Dec 8, 2020 at 14:00.
By comparing to dateColumn to DATEADD(mm, -6, GETDATE()), you can take advantage of any index you might have and generally see better performance. – KyleMit ♦ Commented Mar 8 at 18:37
UPDATE 1: if you just need -6 months, your function did work, but as I mentioned before, -180 days is not the same thing as -6 months. You can still use the AddDays(-180) if you want 180 days, or AddMonths(-6) for 6 months back.
I do not know if the starting date is a month end or not. What I would like to get is a date with the same day of the starting one, should this be a valid one (i.e. 15-Mar, should the input date be 15-Sep), or, otherwise, with the last day of the month (i.e. 28-Feb, should the input date be 31-Aug).
You can implement very easily an "addMonths" function:. function addMonths(date, months) { date.setMonth(date.getMonth() + months); return date; } addMonths(new Date(), -6); // six months before now // Thu Apr 30 2009 01:22:46 GMT-0600 addMonths(new Date(), -12); // a year before now // Thu Oct 30 2008 01:20:22 GMT-0600
SELECT '-12') [months] ORDER BY 1. Then, convert your Time1 and Time2 date points into the 'yyyy-mm' format (Think of these as the coordinate cut points on the whole cloth). Retain the original datetime versions of the points as well: SELECT. Time1 = @Time1, [YYYY-MM of Time1] = CASE.
1. You don't need to pass time() to strtotime, as it is the default. Apart from that, your approach is correct - except that you take date('d') (which is putting out the day) and not date('m') for the month, so echo date('m', strtotime('+6 month')); should do. Nevertheless, I would recommend using the DateTime way, which John stated.
I need to identify the date which is 6 complete months ago. For example: Feb-27, 2012(Today) - It is Feb and we don't count incomplete month, false Feb-01, 2012 - Still Feb so don't count too, false Jan-01, 2011 - Completed, false Dec-01, 2011 - Completed, false Nov-01, 2011 - Completed, false Oct-01, 2011 - Completed, false Sep-01, 2011 ...
For that, I need a measure that is capable of expressing today "one month ago". For example, this month's sales is: MONTH ( TODAY () ) CALCULATE (. 'orders'[SalesAmount]; 'calendar'[month_number] = ThisMonth; 'calendar'[year] = 2017. All time intelligence functions seem to be good to handle columns of date but not scalar values like this case ...
3. I have a simpler answer, which works perfectly for days; for months, it's +-2 days: let today=new Date(); const days_to_subtract=30; let new_date= new Date(today.valueOf()-(days_to_subtract*24*60*60*1000)); You get the idea - for months, multiply by 30; but that will be +-2 days. answered Nov 11, 2020 at 6:36.